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Module DEMO-32-59DEMO-C-32

Sum of Large Digits using while

DEMO-C-32 • Programming in C

Browser-only practice

Problem Statement

Write a C program that reads an integer and calculates the sum of all its digits that are greater than 5.

For example, if the input is 123456789, the digits greater than 5 are 6, 7, 8, and 9. Their sum is 6 + 7 + 8 + 9 = 30.

If there are no digits greater than 5 in the number, output 0.

Note: Handle negative numbers by ignoring the negative sign and working with the absolute value.

Constraints

-2,147,483,648 ≤ n ≤ 2,147,483,647 The program should handle negative numbers by considering their absolute value

Input Format

A single line containing an integer n (-2,147,483,648 ≤ n ≤ 2,147,483,647).

Output Format

A single line containing the sum of all digits in the number that are greater than 5.

Sample Testcases

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Sample #1
Public sample
Input
123456789
Output
30
Explanation
Digits greater than 5: 6, 7, 8, 9. Sum = 6+7+8+9 = 30
Sample #2
Public sample
Input
987654321
Output
30
Explanation
Digits greater than 5: 9, 8, 7, 6. Sum = 9+8+7+6 = 30
Sample #3
Public sample
Input
-123456789
Output
30
Explanation
Negative number. Consider absolute value: 123456789. Digits > 5: 6, 7, 8, 9. Sum = 30
Sample #4
Public sample
Input
12345
Output
0
Explanation
No digits greater than 5. Sum = 0
Sample #5
Public sample
Input
54321
Output
0
Explanation
No digits greater than 5. Sum = 0
Sample #6
Public sample
Input
5
Output
0
Explanation
Single digit 5, which is not greater than 5. Sum = 0

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