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Module DEMO-32-57DEMO-C-32

Leap Year Classification

DEMO-C-32 • Programming in C

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Problem Statement

Problem Description

Write a program that determines whether a given year is a leap year or a common year.

Leap Year Rules

A year is a leap year if it satisfies the following conditions:

  • It is divisible by 4, and If it is divisible by 100, then it must also be divisible by 400 to be a leap year.
  • Otherwise (not divisible by 100), it is a leap year.

In simpler terms:

  1. If the year is divisible by 400 → Leap Year
  2. Else if divisible by 100 → Common Year
  3. Else if divisible by 4 → Leap Year
  4. Otherwise → Common Year

Example

  • 2024: Divisible by 4 but not 100 → LEAP YEAR
  • 1900: Divisible by 100 but not 400 → COMMON YEAR
  • 2000: Divisible by 400 → LEAP YEAR

Constraints

The input must be a positive integer between 1 and 10000 inclusive. Your solution must correctly implement the leap year logic as described.

Input Format

A single integer representing the year.

  • Input: year (integer)
  • Range: 1 ≤ year ≤ 10000

Output Format

Print exactly one of the following strings on a single line:

  • LEAP YEAR if the year is a leap year
  • COMMON YEAR if the year is not a leap year

No extra spaces or formatting.

Sample Testcases

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Sample #1
Public sample
Input
2024
Output
LEAP YEAR
Explanation
2024 is divisible by 4 but not by 100, so it's a leap year
Sample #2
Public sample
Input
2000
Output
LEAP YEAR
Explanation
2000 is divisible by 400, so it's a leap year
Sample #3
Public sample
Input
1900
Output
COMMON YEAR
Explanation
1900 is divisible by 100 but not by 400, so it's not a leap year
Sample #4
Public sample
Input
2023
Output
COMMON YEAR
Explanation
2023 is not divisible by 4, so it's not a leap year
Sample #5
Public sample
Input
10000
Output
LEAP YEAR
Explanation
10000 is divisible by 100 but not by 400, so it's not a leap year

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