المشاريع وتسلسل الموارد

projects = [{"id": "study-dev", "owner": "team-a", "environment": "dev"}, {"id": "study-prod", "owner": "team-a", "environment": "prod"}]
ids = [project["id"] for project in projects]
assert len(ids) == len(set(ids))
assert all(project["owner"] and project["environment"] for project in projects)
print(f"inventory={len(projects)} unique={len(set(ids))}")

inventory=2 unique=2

لسجلين مخترعين معرفان مختلفان ومالكان صريحان دون حساب أوواجهة.

parents = {"project-study": "folder-apps", "folder-apps": "organization-study", "organization-study": None}
path = []
node = "project-study"
while node is not None:
    if node in path:
        raise ValueError("cycle in synthetic hierarchy")
    path.append(node)
    node = parents[node]
print(" -> ".join(path))

project-study -> folder-apps -> organization-study

يكشف النموذج المشروع والمجلد والمؤسسة دون تقييم وصول سحابي.